有趣的猜字游戏 python

引入 【有趣的猜字游戏】如果给你一个给定的范围，让你猜出这个范围内的任意一个数，你怎样才能又快又准确的猜出你？可以采用二分法，比如在一到一百内猜，先猜五十，如果大了就猜二十五，如果小了就猜七十五，按照这样下去很快就能猜出那个数！
程序

import random target = random.randint(0,100) x = int(input("Try to guess the number I'm think of:")) while True: if x > target: x = int(input('Too high! Guess again:')) elif x < target: x = int(input('Too low! Guess again')) else: break print("That's it! Thank for playing!")

请看程序结果

文章图片

这个程序一次就结束了，可是如果用户想多玩几次程序又该怎么改进呢？
改进程序

import randomwhile True:target = random.randint(0,100) x = int(input("Try to guess the number I'm think of:")) while True: if x > target: x = int(input('Too high! Guess again:')) elif x < target: x = int(input('Too low! Guess again:')) else: break choice = input("That's it! Would you like to play again?(yes/no)") if choice == 'no': break print("That's it! Thank for playing!")

请看程序结果