一些小实例|复数的加减乘除C语言实现 1024程序员节|c语言

思路：
1复数的表示：用结构体实现
2复数的加减法：实部虚部分别相加减
复数的乘法：（a+bi)(c+di)=ac-bd+(ad+cb)i
复数的除法：(a+bi)(c+di)=(ac+bd)(cc+dd)+(bc-ad)(cc+d*d)
考虑分母为0的情况
3注意输出格式，考虑虚部为复数和虚部为0的情况
4用switch语句由用户自己选择要进行的操作
5用do…while循环实现多次运算
代码实现

#include #include //用结构体表示复数 typedef struct { double realPart; double imagPart; /* data */ }complex; //定义一个复数 complex assign(double a, double b); //复数的加法 complex add(complex c1, complex c2); //复数的减法 complex sub(complex c1, complex c2); //复数的乘法 complex mul(complex c1, complex c2); //复数的除法 complex div(complex c1, complex c2); void display(complex c); int main() { double realPart, imagPart; complex c1, c2; int adjust=0; do { printf("--------------------------------\n"); printf("欢迎您使用负数计算器\n"); printf("请您输入复数的实部和虚部\n"); scanf("%lf%lf", &realPart, &imagPart); c1 = assign(realPart, imagPart); display(c1); printf("请您输入第二个复数的实部和虚部\n"); scanf("%lf%lf", &realPart, &imagPart); c2 = assign(realPart, imagPart); display(c2); printf("请您选择需要进行的操作\n"); printf("1加法\n2减法\n3乘法\n4除法\n0退出复数计算器\n"); scanf("%d", &adjust); if (adjust==1||adjust==2||adjust==3||adjust==4) { printf("您的计算结果是:"); }switch (adjust) { case 1: display(add(c1, c2)); break; case 2: display(sub(c1, c2)); break; case 3: display(mul(c1, c2)); break; case 4: display(div(c1, c2)); break; default: if (adjust == 0) { printf("谢谢使用"); } else { printf("输入的操作有误，请您重新输入"); } } } while (adjust != 0); printf("感谢您的使用，祝您生活愉快"); return 0; }//定义一个复数 complex assign(double a, double b) { complex c; c.realPart = a; c.imagPart = b; return c; }//复数的加法 complex add(complex c1, complex c2) { assign((c1.realPart + c2.realPart), (c1.imagPart + c2.imagPart)); }//复数的减法 complex sub(complex c1, complex c2) { assign((c1.realPart - c2.realPart), (c1.imagPart - c2.imagPart)); }//复数的乘法 complex mul(complex c1, complex c2) { assign((c1.realPart * c2.realPart - c1.imagPart * c2.imagPart), (c1.imagPart * c2.realPart + c1.realPart * c2.imagPart)); }//复数的除法 complex div(complex c1, complex c2) { double temp = (pow(c1.imagPart, 2) + pow(c2.imagPart, 2)); if (c2.imagPart!=0&&c2.realPart!=0) { assign((c1.realPart * c2.realPart + c1.imagPart * c2.imagPart) / temp, (c1.imagPart * c2.realPart - c1.realPart * c2.imagPart) / temp); } else { printf("除数为0，请重新输入"); } }//输出复数 void display(complex c) { if (c.imagPart > 0) { printf("%lf+%lfi\n", c.realPart, c.imagPart); } else if(c.imagPart<0) { printf("%lf%lfi\n", c.realPart, c.imagPart); } else { printf("%lf\n", c.realPart); } }

【一些小实例|复数的加减乘除C语言实现】运行结果显示：